Question

A car is initially traveling at 17 m/s when the driver steps down hard on the gas pedal

resulting in an acceleration of 3.0 m/s2. How fast will the car be moving 4.0 seconds later? v=29
m/s

Answer 1

29 m/s

Step-by-step explanation:

Acceleration is the rate of change of velocity, i.e, the change in velocity per unit time.

The driver made the car to accelerate at 3 m/s^2. That means than in every second the velocity of the car increased by 3 m/s. Therefore in four seconds its velocity would increase by 3m/s x 4 = 12m/s. Starting with an initial velocity of 17 m/s the final velocity would be 17 m/s + 12 m/s = 29 m/s.