Question

(1) A soil has the following properties: S = 50%, G. = 2.71, w = 18%. Determine the e, , and y. (2 pts)

Answer 1

e = 0.97

`\gamma = 25.859\  gm/cm^3`

Step-by-step explanation:

Given data:

saturation value S = 50%

Specific gravity. G = 2.71

W, water content = 18%

void ratio
`e = (wGs)/(S)`

`=  ( 18* 2.71)/(50)`

e = 0.97

Dry unit weight
`\gamma_d = (Gs \gamma_w)/(1+e)`

where
`\gamma_w` is unit weight of water is 0.99

`= (2.71* 0.99)/(1+0.97)`

`= 1.361 gm/cm^3`

`\gamma = \gamma_d (1 + w)`

`= 1.361 (1+ 18)`

`= 1.361 * 19`

`= 25.859\  gm/cm^3`