Question

The daily production of carbon dioxide from an 780.0 MW coal-fired power plant is estimated to be 4.1480 x 104 tons (not metric).

A proposal has been made to capture and sequester the CO2 at approximately 300 K and 140 atm. At these conditions, the specific volume of CO2 is estimated to be 0.0120 m3/kg.

What volume of CO2 would be collected in a 3.00 year period? Entry field with incorrect answer x 108 m3

Answer 1

volume of Co_2 = 494458644.1 m^3

Step-by-step explanation:

Daily production of
`Co_2\ is \ 4.4180* 10^4 tons`

we know that one tons equal to 907.18 kg

so, daily production is
`4.4180* 10^4 * 907.18 kg/day`

Mass of produced Co_2 =
`Daily production* 3* 365`

`=4.4180* 10^4 * 907.18 * 3* 365`

`= 4.180* 10^(10) kg`

`Co_2` specific volume is
`0.012 m^3/kg`

volume of
`Co_2` in 3 year
`= Mass\ of\ produced\ Co_2* Co_2\ specific\ volume`

`volume =  4.180* 10^(10) * 0.012`

`= 494458644.1 m^3`