Question

For the following dimensional equation, find the base dimensions of the parameter f. MM" = a cos(fL) Solution

Answer 1

`L^(-1)`.

Step-by-step explanation:

Given that

MM''= a cos(fL)

We know that all trigonometric function are dimensional less.So fL should be dimension less quantity.

Property Dimension

Length L

Mass M

Force
`MLT^(-1)`

Acceleration
`LT^(-2)`

Velocity
`LT^(-1)`

Torque
`ML^2T^(-1)`

Time
`T^(-1)`

So in the given question ,dimension of L is L so the dimension of f will become
`L^(-1)`.