Question

Calculate the fraction of atom sites that are vacant for silver at 552°C. Assume an energy for vacancy formation of 0.63 eV/atom.

Answer 1

`(N_C)/(N) = 1.42* 10^(-4)`

Step-by-step explanation:

given data:

temperature = 552 degree celcius = 825 Kelvin

energy for vacancy formation is given as 0.63 eV/atom

fraction of atom can be obtained from following formula

`N_C = N e^{(-Q_V)/(kT)}`

Where, K IS BOLTZMAN CONSTANT
`= 8.62* 10^(-5)eV/K`

`(N_C)/(N) =e^{(-0.63)/(8.62* 10^(-5) * 825)`

`(N_C)/(N) = e^(-8.8858)`

`(N_C)/(N) = 1.42* 10^(-4)`