Question

Two propane-butane mixtures are contained in separate containers. The first mixture contains 30 wt% propane, and the second contains 60 wt% propane. If 1,000 g of the first mixture is combined with 1,200 g of the second, what are the mass and compositions of the product?

Answer 1

750 grams is the mass of product and 34.09% is the compositions of the product.

Step-by-step explanation:

Container 1 , 30% of propane by mass:

Container 2 , 60% of propane by mass:

Mass of mixture in container-1 = 1000 g

Mass of propane in 1000 g of mixture = m

m=
`(30)/(100)* 1000 g= 300g`

Mass of mixture in container-2 = 1200 g

Mass of propane in 1200 g of mixture = m'

m'=
`(60)/(100)* 1200 g= 720 g`

After mixing 1000 grams and 1200 grams of mixture

Final mass of mixtures = 1000 g + 1200 g = 2200 g

Final mass of propane = 300 g+ 720 g = 750 g

Composition of propane after mixing of mixtures :

`\%=(750 g)/(2200 g)* 100=34.09\%`