Question

A process stream contains 450 mol/s benzene and 375 mol/s toluene. Calculate the mole fraction of benzene in the process stream.

Answer 1

0.5455

Step-by-step explanation:

The moles of benzene in the process stream in 1 sec = 450 moles

The moles of toluene in the process stream in 1 sec = 375 moles

So, according to definition of mole fraction:

`Mole\ fraction\ of\ benzene=\frac {n_(benzene)}{n_(benzene)+n_(toluene)}`

Applying values as:

`Mole\ fraction\ of\ benzene=\frac {450}{450+375}`

Mole fraction of benzene in the process stream = 0.5455