Question

1.

A ball is thrown into the air with an initial velocity of 22 meters per second.
The quadratic function h(t) = -4.9t2 + 22t + 5.5 represents the height of
the ball above the ground, in meters, with respect to time t, in seconds.
Part A: Determine h(3) and explain what it represents.

Answer 1

The ball throw into the air with an initial velocity of 22 meters per second is 27.4 meters above the ground after 3 seconds.

Explanation:

The quadratic function
`h(t) = -4.9t^2 + 22t + 5.5` represents the height of the ball above the ground, h(t), in meters, with respect to time, t, in seconds.

To find h(3), substitute t = 3 into the function expression:

`h(3)=-4.9\cdot 3^2+22\cdot 3+5.5\\ \\=-4.9\cdot 9+66+5.5\\ \\=-44.1+71.5\\ \\=27.4`

Meaning: the ball throw into the air with an initial velocity of 22 meters per second is 27.4 meters above the ground after 3 seconds.