Question

Liquid dimethyl disulfide (CH3SSCH3) flows through a pipe with a mass flow rate of 86.0 g's. Given that the density of dimethyl disulfide is 1.0625 g/cm, find: The molar flow rate in molimin: Number mol/min The volumetric flow rate in L/hr.

Answer 1

Step-by-step explanation:

Molar mass of
`CH_(3)SSCH_(3)` is 94 g/mol. As it is known that number of moles is equal to mass of a substance divided by its molar mass.

Then, calculate the number of moles as follows.

No. of moles =
`(86.0 g)/(94 g/mol)` in 1 s

= 0.914 mol

So, in 60 sec number of moles will be equal to 0.914 x 60 = 54.89 mol/min.

Hence, the molar flow rate = 54.89 mol/min

Also, density is equal to mass of a substance divided by its volume.

Density =
`(mass)/(volume)`

Volume =
`(mass)/(Density)`

=
`(86.0 g)/(1.0625 g/cm^(3))`

= 80.941
`cm^(3)`

As, 80.941
`cm^(3)` of volume flows in 1 s . Therefore, flow of volume in 1 hour will be calculated as follows.

In 1 hr = 80.941
`cm^(3) * 3600`

= 291388.24
`cm^(3)/hr`

Since, 1
`cm^(3)` = 0.001 L.

So, 291388.24
`cm^(3)/hr * 0.001 L/cm^(3)`

= 291.38824 L/hr

Thus, we can conclude that molar flow rate in mol/min is 54.89 mol/min and the volumetric flow rate in L/hr is 291.38824 L/hr.