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Given m< LOM = 3x +38 m< MON= 9x+28 find m< LOM:
PLEASE HELP ME !!!

Given m< LOM = 3x +38 m< MON= 9x+28 find m< LOM: PLEASE HELP ME !!!-example-1
User Lolero
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1 Answer

1 vote

Answer:

The answer to your question is: m∠LOM = 44°

Explanation:

Data

m< LOM = 3x +38

m< MON= 9x+28

m< LOM = ?

Process

They are complementary angles

m∠LOM + m∠MON = 90°

3x + 38 + 9x + 28 = 90°

12x + 66 = 90°

12x = 90 - 66

12x = 24

x = 24/12

x = 2

m∠LOM = 3(2) + 38

= 6 + 38

= 44°

m∠ MON = 9(2) + 28

m∠MON = 18 + 28

m∠MON = 46°

User AEMLoviji
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