Question

Tasia need 75 L of a 40% solution of alcohol she has 20% solution and 50% solution available how many liters of the 20% solution how many what is the 50% solution should she mix to get 40% solution

Answer 1

• 50 liters of 50% solution
• 25 liters of 20% solution

Explanation:

Let x represent the number of liters of 50% solution required. Then (75-x) is the number of liters of 20% solution needed. The total amount of alcohol in the final mix is ...

0.50x + 0.20(75 -x) = 0.40(75)

0.30x + 15 = 30 . . . . simplify

0.30x = 15 . . . . . . . . . subtract 15

x = 15/0.30 = 50

50 liters of 50% solution and 25 liters of 20% solution should be mixed.