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If m < nqm = 2x+8 and m < pqr = x+22 find the value of x
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If m < nqm = 2x+8 and m < pqr = x+22 find the value of x

User Abhinav Tyagi
by
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1 Answer

2 votes

Answer:

The value of x is 14

Explanation:

see the attached figure to better understand the problem

we have that

m∠NQM=m∠PQR -----> given problem

substitute the given values and solve for x


2x+8=x+22

Group terms that contain the same variable and combine like terms


2x-x=22-8\\x=14

If m < nqm = 2x+8 and m < pqr = x+22 find the value of x-example-1
User Nemmy
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