Question

A mixture of methanol and methyl acetate contains 7.0 weight percent methanol. Determine the number of gmols of methanol in 300.0 kilograms of the mixture.

Answer 1

656,25 moles of CH3OH

Step-by-step explanation:

If the mixture has 7% of weight in methanol (CH3OH), it means that for every 100 kg of the mixture there are 7 kg of methanol.

To solve the problem we just use this relation and convert the kilograms of methanol to gmoles of methanol using the molecuar weight of the methanol (32g/mol):

`300 kgmixture*(7kgCH3OH)/(100kg)*(1000g)/(1kg)*(1molCH3OH)/(32g)=656,25molesCH3OH`