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3 votes
What is the simplified form of StartRoot 64 x Superscript 16 Baseline EndRoot?

User Saad Qamar
by
4.8k points

2 Answers

7 votes

Answer:

8x8

Explanation:

so B

User Teamnorge
by
5.4k points
5 votes

Answer:


8x^8 (Please see my interpretation of the problem.)

The problem:

Simplify
\sqrt{64x^(16)} (Please tell me if I did or didn't interpret your problem correctly. Thank you!)

Explanation:


\sqrt{64x^(16)} (Given)


√(64)\sqrt{x^(16)} (if u and v are positive then
√(uv)=√(u)√(v))


8\sqrt[2]{x^(16)} (
√( )=\sqrt[2]{})


8x^{(16)/(2)} (
\sqrt[n]{x^m}=x^(m)/(n))


8x^8 (simplified/reduced the fractional-exponent)

User Nemelis
by
5.3k points