Question

When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the reaction below. How many grams of hydrogen were required to form 3.00 moles of water?

Answer 1

The answer to your question is: 6 grams of hydrogen

Step-by-step explanation:

Data

3.0 moles of hydrogen

1.5 moles of oxygen

3 moles of water

# of grams of hydrogen required to form 3 moles of water?

Equation

H₂ + 1/2 O₂ ⇒ H₂O

3 mole 1.5 moles 3 moles

Atomic weight of H₂ = 2 g

1 mole ----------------------- 2 g

3 moles --------------------- x

x = 3(2)/1 = 6 grams of hydrogens

Answer 2

6.05 g

Step-by-step explanation:

Hello! The answer to your question is 6.05 g of hydrogen, in order to form 3.00 moles of water. Hope this helps you!