31.4k views
5 votes
How many grams of NH3 are needed to provide the same number of molecules as in 0.35 g of SF6 ?

User Ubermonkey
by
4.8k points

2 Answers

3 votes

Final answer:

To find the mass of NH3 that has the same number of molecules as 0.35 g of SF6, we can use the molar mass and stoichiometry. By comparing the molar mass of NH3 and SF4, we can calculate the mass of NH3.

Step-by-step explanation:

In this question, we are given the amount of SF6 and we need to find the amount of NH3 that has the same number of molecules. To solve this, we need to use the molar mass and Avogadro's number. The balanced chemical equation for SF6 is:

SF6(g) ➔ SF4(g) + F2(g)

From the equation, we can see that 1 mol of SF6 produces 1 mol of SF4. Therefore, we can calculate the molar mass of SF4 and NH3 (which has the same number of molecules as SF6) and use the ratio to find the mass of NH3. Use the equation:

mass of NH3 = (molar mass of NH3 / molar mass of SF4) × mass of SF6

User ZINE Mahmoud
by
4.6k points
6 votes

Answer:

  • There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.

Step-by-step explanation:

Using the molar mass of the chemical formula SF₆ you can find the number of moles of molecules in 0.35 g of such substance. Then, using the molar mass of NH₃, you can find mass in grams corresponding to the same number of molecules.

1. Find the molar mass of SF₆:

Atom atomic mass number of atoms total mass in 1 mole

S 32.065 g/mol 1 32.065 g

F 18.998 g/mol 6 6 × 18.998 = 113.988 g

=====================

molar mass of SF₆ = 146.053 g/mol

2. Find the number of moles in 0.35 g of SF₆:

  • number of moles = mass in grams / molar mass
  • number of moles = 0.35 g / 146.053 g / mol = 0.0024 mol

3. Find the molar mass of NH₃:

Atom atomic mass number of atoms total mass 1 mole

N 14.007 g/mol 1 14.007 g

H 1.008 g/mol 3 3 × 1.008 g = 113.988 g

=====================

molar mass of NH₃ = 17.031 g/mol

4. Find the mass in 0.0024 mol of NH₃:

  • mass in grams = number of moles × molar mass

  • mass = 0.0024 mol × 17.031 g/mol ≈ 0.041 grams

5. Conclusion:

There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.

User David Mear
by
5.3k points