Answer:
- There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.
Step-by-step explanation:
Using the molar mass of the chemical formula SF₆ you can find the number of moles of molecules in 0.35 g of such substance. Then, using the molar mass of NH₃, you can find mass in grams corresponding to the same number of molecules.
1. Find the molar mass of SF₆:
Atom atomic mass number of atoms total mass in 1 mole
S 32.065 g/mol 1 32.065 g
F 18.998 g/mol 6 6 × 18.998 = 113.988 g
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molar mass of SF₆ = 146.053 g/mol
2. Find the number of moles in 0.35 g of SF₆:
- number of moles = mass in grams / molar mass
- number of moles = 0.35 g / 146.053 g / mol = 0.0024 mol
3. Find the molar mass of NH₃:
Atom atomic mass number of atoms total mass 1 mole
N 14.007 g/mol 1 14.007 g
H 1.008 g/mol 3 3 × 1.008 g = 113.988 g
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molar mass of NH₃ = 17.031 g/mol
4. Find the mass in 0.0024 mol of NH₃:
- mass in grams = number of moles × molar mass
- mass = 0.0024 mol × 17.031 g/mol ≈ 0.041 grams
5. Conclusion:
There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.