Question

An object with a mass of 100 kg is dropped from a height of 20 m. If the velocity of the object before hitting the ground is 15 m/s, is there a loss of energy in the form of heat? If so, how much? Assume, g= 9.8 m/s^2

Answer 1

Yes, there is a loss of 8350 J of energy in the form of heat

Step-by-step explanation:

The principle of energy conservation is described mathematically

as the energy conservation equation as follows:

ΔK+ΔU=Q+W

where:

• ΔK: changes in kinetics energy [J]
• ΔU: changes in potential energy [J]
• Q: gain or loss of heat[J]
• W: work done by the system or in the system[J]

Analyzing each term of the equation:

`ΔK=(1)/(2)mv_(f) ^(2)  - \x]frac{1}{2}mv_(i) ^(2)=(1)/(2)*100*15^(2) - (1)/(2)*100*0^(2)=11250 J`

ΔU=
`mgh_(f)-mgh_(i)=100*9,8*0-100*9,8*20=-19600[J]`

Q=?

W=0 [J]

Replacing in the main equation:

11250-19600=Q+0

Q= -8350 [J]

So, the answer is YES, there is a loss of 8350 J of energy in the form of heat.