Question

The mass flow rate of gasoline leaving a refinery is 1610 kg/min. The specific gravity of a gasoline is 0.700.

A retail gasoline pump is able to fill a 20.0 gallon automobile tank in 1.80 minutes. What is the mass flow rate deliverd by the gasoline pump in lbm/min?

Answer 1

mass flow = 64.9086 Lbm/min

Step-by-step explanation:

SG = 0.700 = ρ gas / ρ H2O

∴ ρ H2O = 1000 Kg/m³

⇒ ρ gas = 700 Kg/m³

∴ F auto tank = 20.0 gal / 1.8 min = 11.11 gal/min * ( m³/264.172 gal)

⇒ F auto = 0.042 m³/min

⇒ mass flow = 0.042 m³/min * (700 Kg/m³) * ( 2.20462 Lbm/ Kg )

⇒ mass flow = 64.9086 Lbm/min