Question

Determine how many gmol, kmol, and lbmols there are in 50 kilograms of n-hexane.

Answer 1

Answer: 581 gmol

0.581 kmol

`1.28* 10^(-3)lbmol`

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(50* 1000g)/(86g/mol)=581mol`

1. The conversion for mol to gmol

1 mol = 1 gmol

581 mol=
`(1)/(1)* 581=581gmol`

2. The conversion for mol to kmol

1 mol = 0.001 kmol

581 mol=
`(0.001)/(1)* 581=0.581kmol`

3. The conversion for mol to lbmol

1 mol =
`2.2* 10^(-3)lbmol`

581 mol=
`(2.2* 10^(-3))/(1)* 581=1.28* 10^(-3)lbmol`