Question

Estimate the density of a mixture of50% acetone and 50% water by volume additivity

Answer 1

892 grams/liter

Step-by-step explanation:

in order to calcuñate this you jus have to add the percentage of the volume of both water has a density of 1000 gms/liter or 1 gram/mililter and the acetone is 784 g/l so if that is 50%-50% you multiply that by .5 and you add them up and get the density of the mix of them both:

1000*,5= 500g/l

784*,5=392 g/l

500+392=892g/l

So the density of a mixture 50-50 of water and acetone would be 892 g/l

Answer 2

751.8kg/m3

Explanation:

Assuming water's density is 1,000 kg/m3 and acetone's density is 791kg/m3

we use the formula

`(1)/(p) = summatory (xi)/(pi)`

where 1/p is the density of the mixture, xi is the mass fraction and pi is the individual density of the components of the mixture.

To calculate xi we consider that acetone and water are in a 50% proportion, this means xi is 0.5 for both substances, now we can substitute in the formula:

`(1)/(p) = (0.5)/(1000) + (0.5)/(791) = 0.00133`

now we obtain p.

p=751.8kg/m3

I hope you find this information useful! good luck!