Question

Consider the redox reaction below.

Which equation is a half reaction that describes the reduction that is taking place?

Answer 1

Answer: The half reaction that describes the reduction reaction is
`Fe^(2+)(aq.)+2e^-\rightarrow Fe(s)`

Step-by-step explanation:

Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

`X\rightarrow X^(n+)+ne^-`

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

`X^(n+)+ne^-\rightarrow X`

For the given chemical reaction:

`Mg(s)+Fe^(2+)(aq.)\rightarrow Mg^(2+)(aq.)+Fe(s)`

The half reactions follows:

Oxidation half reaction:
`Mg(s)\rightarrow Mg^(2+)(aq.)+2e^-`

Reduction half reaction:
`Fe^(2+)(aq.)+2e^-\rightarrow Fe(s)`

Hence, the half reaction that describes the reduction reaction is
`Fe^(2+)(aq.)+2e^-\rightarrow Fe(s)`

Answer 2

1)

Step-by-step explanation:

Fe+2 + 2e -> Fe

The element that is reduced gains electrons. In this case Fe is gaining electrons