Question

How many calories would be needed to heat 5.0 lbs of copper from 22 degrees C to 80.0 degrees C? C for copper = 0.092

Answer 1

`1.21* 10^4` cal would be needed to heat 5.0 lbs of copper from 22 degrees C to 80.0 degrees C.

Step-by-step explanation:

`Q=m * c * \Delta T`

where

`\Delta T` = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for copper 0.092 cal/(g℃))

m is the mass of water

plugging in the values

`$Q=5.01 b s * 0.092 \frac{c a l}{g^(\circ) \mathrm{c}} *\left(80.0^(\circ) \mathrm{C}-22^(\circ) \mathrm{C}\right)$`

Please Note:

1 lb = 453.592grams

So,

5 lbs = 5 × 453.592g = 2268 g

`$\begin{aligned} Q &=2268 g * 0.092 \frac{c a l}{g^(\circ) \mathrm{C}} * 58^(\circ) \mathrm{C} \\\\ Q &=12102 \mathrm{cal} \end{aligned}$`

`=1.21*10^4` cal (Answer)