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Find the area of this irregular polygon.

Find the area of this irregular polygon.-example-1

1 Answer

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Answer:

970m^{2}

Explanation:

This polygon can be divided in two figures: one is a triangle, an the other one is a square.

We'll begin calculating the triangle's area, using the following formula:


At= (b.h)/(2)

Where:


H= height = 30 m


B = 9 m + 9 m + 20 m = 38 m

As you can see, I added both sides of the triangle that measure 9 m and also the lenght of the square that measures 20 m! This added up is what the base of the triangle measures on total.


At= (38 m .30 m)/(2)


At= (1140 m^(2) )/(2)


At= 570 m^(2)

Now we are going to calculate the square's area, that is much more simple:


As= L^(2)

Where:


L=20 m


As= (20 m)^(2) = 400m^(2)

To know the whole figure's area, we add up both areas:


A = At+As = 570m^(2) +400m^(2)=970m^(2)

User David Andres
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