Question

given line passes through the points (-4, -3) and( 4, 1) what is the equation in point slope form of the line that's perpendicular to the given line and passes through the point (-4,3)

Answer 1

y + 3= one- fourth (x +4

Explanation:

Answer 2

y= -2x-5

Explanation:

First find the gradient of the first line

`m = (y2 - y1)/(x2 - x1)`

m=

`(1 - - 3)/(4 - - 4)`

m=

`(4)/(8)`

m=1/2

From this we can find the gradient of the perpendicular line, or the normal.

m1 × m2 = -1

Replace m1 with 1/2

1/2 × m2 = -1

m2= -2

Substitute values into

y-y1=m (x-x1)

y-3=-2 (x+4)

y-3=-2x -8

y=-2x-5