Answer:
Displacement CO=2.15 Km
Average velocity = 1.99 Km/h
Step-by-step explanation:
Given
Total time = 1.08 h
OA= 1.62 Km
AB=0.246 Km
BC=3.08 Km
θ=50.4°
CE=3.08 sin50.4° =2.37 Km
BE=3.08 cos50.4° =1.96 Km
CE=AB+OD
OD=CE-AB
OD=2.37-0.246
OD=2.124 Km
BE=CD+OA
CD=BE-OA
CD=1.96-1.62
CD=0.34 Km
Now CO


CO=2.15 Km
So the displacement CO=2.15 Km
Average velocity =Displacement/Time
Average velocity = 2.15/1.08 Km/h
Average velocity = 1.99 Km/h