Question

Find two consecutive odd integers whose sum is 116.

Answer 1

57 and 59

Explanation:

Let's indicate x as an even number

Hence, let x+1 be the first odd integer

Let x+3 be the second consecutive odd integer

(x+3)+(x+1) = 116

2x+4=116

2(x+2) = 116

x+2 = 116/2

x+2 = 58

x=58-2

x=56

Hence, first integer= (x+1) = 56+1 = 57

Second integer= (x+3) = 56+3 = 59

Hope this helps!

Answer 2

57 and 59

Explanation:

x+(x+2) = 116

2x+2 = 116

Subtract 2 from both sides

2x=114

Divide both sides by 2

x=57

57 is the first odd integer, so the second one is 59

59+57 = 116