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5. How much power is dissipated when 0.2 ampere of current flows through a 100-ohm resistor ?​
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5. How much power is dissipated when 0.2 ampere of current flows through a 100-ohm resistor ?​

User Mahendren Mahisha
by
3.4k points

1 Answer

9 votes

Answer:

P=I*I*R

Where P is power

I is current

R is Resistance

P=2*2*100

P=400W

Step-by-step explanation:

Power is the rate of doing work.

From the Ohm’s law V=IR

Power=I*I*R

User Vix
by
3.0k points
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