Question

How would you do this algebra question?

Answer 1

`\bf \left( \cfrac{~~\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 4\cdot 2}{~~\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 7} \right)^2 *\left( \cfrac{8^0}{7^(-3)} \right)^3* 7^(-9)\implies \left( \cfrac{4\cdot 2}{7} \right)^2 * \left( \cfrac{1}{7^(-3)} \right)^3* 7^(-9)`

`\bf \left( \cfrac{8}{7} \right)^2 * \left( \cfrac{1^3}{7^(-3\cdot 3)} \right)* 7^(-9)\implies \left( \cfrac{8^2}{7^2} \right) * \left( \cfrac{1}{7^(-9)} \right)* 7^(-9)\implies \cfrac{8^2}{7^2}* \cfrac{7^(-9)}{7^(-9)} \\\\\\ \cfrac{8^2}{7^2}\cdot 1\implies \cfrac{8^2}{7^2}\implies \cfrac{64}{49}`

Answer 2

Add then I would divide it