Answer: Q = 6,440
Step-by-step explanation:
Annual demand = D = 12,200
Setting up cost = O = $51
Production rate per year = P = Operating days × Producing capability
= 300 days a year × 100 per day
= 30,000
Holding cost per year = H = $0.05 per light
![X = (D)/(P)](https://img.qammunity.org/2020/formulas/business/college/63y6a66okhdlygbe7p461ysjdsdrnmp9zs.png)
![X = (12,200)/(30,000)](https://img.qammunity.org/2020/formulas/business/college/i9a7yfpz1enjmhb5walgu1wvhlx3ril4fp.png)
= 0.4
Therefore,
Optimal size of the production run, Q
![=\sqrt{(2OD)/(H(1-x)) }](https://img.qammunity.org/2020/formulas/business/college/xl7m9cwmp65l3ghu9gztv3vhistf6dcf0w.png)
![=\sqrt{(2*51*12,200)/(0.05(1-0.4))}](https://img.qammunity.org/2020/formulas/business/college/4t6n9ckxpjhau36m4vsfptsc5t5z3m0ars.png)
![=\sqrt{(1,244,400)/(0.03)}](https://img.qammunity.org/2020/formulas/business/college/2hol6qjttb2nkby0xjrrogb03bfvtt4fbx.png)
= 6,440.49
Q = 6,440