Question

Two masses are attracted by a gravitational force of 7 N.

(a) What will the force of attraction be if the distance between these two masses is quartered?

Answer 1

The answer to your question is: F = 0.4375 N. The force will be 16 times lower than with the first conditions.

Step-by-step explanation:

Data

F = 7 N

F = ? if the masses is quartered

Formula

`F = (Km1m2)/(r2)`

Process

Normal conditions F = Km₁m₂/r² = 7

When masses quartered F = K(m₁/4)(m₂/4)/r² = ?

F = K(m₁m₂/16)/r²

F = K(m₁m₂/16r² = 7/16 = 0.4375 N