Question

Solve the equation.
3x^2+40=-x^2-56

Answer 1

x = ± 2i
`√(6)`

Explanation:

Given

3x² + 40 = - x² - 56 ( add x² to both sides )

4x² + 40 = - 56 ( subtract 40 from both sides )

4x² = - 96 ( divide both sides by 4 )

x² = - 24 ( take the square root of both sides )

x = ±
`√(-24)`

= ±
`√(4(6)(-1))` → note
`√(-1)` = i

= ± 2i
`√(6)`