The solution for system of equations x-y=6 ,3 x-2 y=22 is x = 10 and y = 4
Solution:
Using substitution method of algebraic equations,
x - y = 6 --------equation 1
3x - 2y = 22 --------equation 2
Multiplying equation 1 by 2, equation 1 becomes
2 x - 2 y = 12
Multiplying equation 2 by -1, equation 2 becomes,
-3 x + 2 y = -22
Solving,
2 x - 2 y = 12
-3 x + 2 y = -22
-x = -10
x = 10
Substitute x = 10 in equation 1, 10 - y = 6
y = 10 -6
y = 4