Question

In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-19 C. If a single droplet was found to have a total charge of -9.60×10-19 C then how many excess electrons are contained within the drop?

Answer 1

Number of electrons, n = 6

Step-by-step explanation:

Total charge in a single droplet,
`q=-9.6* 10^(-19)\ C`

The measured charge of any single droplet,
`e=-1.6* 10^(-19)\ C`

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

`q=ne`

`n=(q)/(e)`

`n=(-9.6* 10^(-19))/(-1.6* 10^(-19))`

n = 6

So, there are 6 electrons contained within the drop. Hence, this is the required solution.