Question

A mass of 10 g of oxygen fill a weighted piston–cylinder device at 20 kPa and 110°C. The device is now cooled until the temperature is 0°C. Determine the change of the volume of the device during this cooling.

Answer 1

The change of the volume of the device during this cooling is
`14.3*10^(-3)\ m^3`

Step-by-step explanation:

Given that,

Mass of oxygen = 10 g

Pressure = 20 kPa

Initial temperature = 110°C

Final temperature = 0°C

We need to calculate the change of the volume of the device during this cooling

Using formula of change volume

`\Delta V=V_(2)-V_(1)`

`\Delta V=(mR)/(P)(T_(2)-T_(1))`

Put the value into the formula

`\Delta V=(0.3125*0.0821)/(2.0265*10^(9))(383-273)`

`\Delta V=14.297\ L`

`\Delta V=14.3*10^(-3)\ m^3`

Hence, The change of the volume of the device during this cooling is
`14.3*10^(-3)\ m^3`