Question

At high speeds, a particular automobile is capable of an acceleration of about 0.540 m/s^2. At this rate, how long (in seconds) does it take to accelerate from 91.0 km/hr to 104 km/hr?

Answer 1

t = 6.68 seconds

Step-by-step explanation:

The acceleration of the automobile,
`a=0.54\ m/s^2`

Initial speed of the automobile, u = 91 km/hr = 25.27 m/s

Final speed of the automobile, v = 104 km/hr = 28.88 m/s

Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :

`t=(v-u)/(a)`

`t=(28.88-25.27)/(0.54)`

t = 6.68 seconds

So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.