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The pilot of an aircraft wishes to fly due west in a 33.9 km/h wind blowing toward the south. The speed of the aircraft in the absence of a wind is 195 km/h. (a) In what direction should the aircraft head? (b) What should its speed relative to the ground be?

User Eliot Ball
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1 Answer

3 votes

Answer:
\theta =9.96^(\circ) North of west

Step-by-step explanation:

Given

Plane wishes to fly in west

but wind with speed 33.9 km/h towards south obstructing its path

so plane must fly at an angle of \theta w.r.t west such that it final velocity is towards west

Plane absolute speed=195 km/h

To fly towards west velocity in Y direction should be zero

thus
195sin\theta =33.9


\theta =9.96^(\circ)

so Plane should head towards
9.96^(\circ) North of west in order to fly in west.

So plane

actual velocity is


v=-195cos9.96\hat{i}+195sin9.96\hat{j}

User Sujeet Kumar
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