Question

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initial velocity of +6500 m/s, while rocket B has an initial velocity of +8700 m/s. After a time t both rockets are again side by side, the displacement of each being zero. The acceleration of rocket A is -13 m/s2. What is the acceleration of rocket B?

Answer 1

The acceleration of rocket B is -17.4 m/s².

Step-by-step explanation:

Given that,

Initial velocity of rocket A = 6500 m/s

Final velocity of rocket B = 8700 m/s

Acceleration of rocket A = -13 m/s²

Displacement of both rocket is zero.

We need to calculate the time of rocket A

Using equation of motion

`S_(A)=ut+(1)/(2)at^2`

Put the value into the formula

`0=6500t+(1)/(2)*(-13)* t^2`

`t=1000\ sec`

We need to calculate the acceleration of rocket B

Using equation of motion

`S_(B)=ut+(1)/(2)at^2`

Put the value in the formula

`0=8700*1000+(1)/(2)* a*(1000)^2`

`a=(8700*1000*2)/((1000)^2)`

`a=-17.4\ m/s^2`

Hence, The acceleration of rocket B is -17.4 m/s².