Answer:
The reuired probability is 0.756
Explanation:
Let the number of trucks be 'N'
1) Trucks on interstate highway N'= 76% of N =0.76N
2) Truck on intra-state highway N''= 24% of N = 0.24N
i) Number of trucks flagged on intrastate highway = 3.4% of N'' =
![(3.4)/(100)* 0.24N=0.00816N](https://img.qammunity.org/2020/formulas/mathematics/college/1uw40u8p8hgcqeyr4g5pjizxilg2y0uh4t.png)
ii) Number of trucks flagged on interstate highway = 0.7% of N' =
![(0.7)/(100)* 0.76N=0.00532N](https://img.qammunity.org/2020/formulas/mathematics/college/6g6767mstrnlf4jh3zpvsndiif2ayye58t.png)
Part a)
The probability that the truck is an interstate truck and is not flagged for safety is
![P(E)=P_(1)* (1-P_(2))](https://img.qammunity.org/2020/formulas/mathematics/college/7s1j8ce4iql9ikb2h6slo92ry5egw7dzmo.png)
where
is the probability that the truck chosen is on interstate
is the probability that the truck chosen on interstate is flagged
![\therefore P(E)=0.76* (1-0.00532)=0.756](https://img.qammunity.org/2020/formulas/mathematics/college/wk9waceegpy7halcsx6mrx3tqy0xw3r2bj.png)