Answer:
the vertical height reached by the puck is 580.47 m
Step-by-step explanation:
given,
mass of hockey puck = 200 g
angle of inclination (θ )= 30°
μs = 0.40
μk = 0.30
initial velocity = 93 m/s
acceleration of pluck upwards,
a = - g (cosθ × μk +sin θ)
a = - 9.81 × (0.3 × cos 30° +sin 30°)
a = -7.45 m/s²
now,
s =
![(u^2)/(2a)](https://img.qammunity.org/2020/formulas/physics/college/ko002dsa6tmvapchu37eg4yryt024n507q.png)
s =
![(93^2)/(2* 7.45)](https://img.qammunity.org/2020/formulas/physics/college/t33srrdjzv590feptga1phoera7lk9m0y6.png)
s = 580.47 m
the vertical height reached by the puck is 580.47 m