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The base of this regular right pyramid is a square.

What is its surface area?

The base of this regular right pyramid is a square. What is its surface area?-example-1

2 Answers

6 votes

Answer:

○ C) 256 in.²

Explanation:

{a}^{2} + 2a \sqrt{ \frac{ {a}^{2}}{4} + {h}^{2} } = S. A. \\ \\ {8}^{2} + 2(8) \sqrt{ \frac{{8}^{2}}{4} + {12}^{2}} = 64 + 64\sqrt{10}\\ \\ 64\sqrt{10} ≈ 266,3857703 ≈ 256

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User Syed Nasir Abbas
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1 vote

Answer:

256

Explanation:

User Kasperi
by
8.0k points

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