Question

A ball rolls over the edge of a platform with a horizontal velocity of magnitude v. The height of the platform is 1.6 m and the horizontal range of the ball from the base of the platform is 20 m. What is the magnitude of v if air resistance is negligibly small?

Answer 1

v = 35.08 m/s

Step-by-step explanation:

A ball rolls over the edge of a platform with a horizontal velocity of magnitude v.

The horizontal range of the ball from the base of the platform is, x = 20 m

Horizontal velocity,

`v=(x)/(t)`

`v=(20)/(t)`..............(1)

Vertical distance, y = 1.6 m

Vertical distance is given by :

`y=ut+(1)/(2)gt^2`

u = 0

`1.6=(1)/(2)* 9.8t^2`

t = 0.57 seconds

Put the value of t in equation (1) as :

`v=(20)/(0.57)`

v = 35.08 m/s

So, the horizontal velocity of the ball is 35.08 m/s. Hence, this is the required solution.