Answer:
The magnitude of the velocity of boat w.r.t ground is 6.2015 m/s
Solution:
As per the question;
Width of the river, w = 216 m
Uniform speed of boat due east,
![u_(x) = 2.2\hat{i} m/s](https://img.qammunity.org/2020/formulas/physics/high-school/rul1g9xnogl40j7dy621ss3ir8x4yhnmso.png)
Angle in north west direction,
![\theta = 34^(\circ)](https://img.qammunity.org/2020/formulas/physics/high-school/76p2hs23hxq8opjddh10qpdk9ae5zig5j7.png)
Velocity of the boat relative to water,
![v_(bw) = 7.9m/s](https://img.qammunity.org/2020/formulas/physics/high-school/f1fyl4y53b88ndqrhrq5fdtu32905whbdj.png)
Now,
Velocity of the boat relative to the water is given by:
![v_(bw) = -7.9cos34^(\circ)\hat{i} + 7.9sin34^(\circ)\hat{j}](https://img.qammunity.org/2020/formulas/physics/high-school/uoedmh1jlpqgboyoeatudyip4dyi3kpity.png)
![v_(bw) = - 6.55\hat{i} + 4.42\hat{j} m/s](https://img.qammunity.org/2020/formulas/physics/high-school/n4o6cozz3ugum1w6nl850opeubfl7h77yr.png)
Also, velocity of water w.r.t ground is
![v_(wg) = u_(x) = 2.2\hat{i} m/s](https://img.qammunity.org/2020/formulas/physics/high-school/2dwjzrpjnh9ad5cj0ytkkrgjvr1hs9179n.png)
Now,
Magnitude of the velocity of boat w.r.t ground is given by:
![v_(bg) = v_(bw) + v_(wg)](https://img.qammunity.org/2020/formulas/physics/high-school/f3iqeehl1ms2kw60t5nv75u7z9aixjeos0.png)
![v_(bg) = - 6.55\hat{i} + 4.42\hat{j} + 2.2\hat{i}](https://img.qammunity.org/2020/formulas/physics/high-school/yir5rvrp39a045s4750zwkcxbq1adct62p.png)
![v_(bg) = - 4.35\hat{i} + 4.42\hat{j} m/s](https://img.qammunity.org/2020/formulas/physics/high-school/27corvzgojyrddvtmqtgxeb7vakqdxxufw.png)
![|v_(bg)| = \sqrt{(- 4.35)^(2) + (4.42)^(2)} = 6.2015\ m/s](https://img.qammunity.org/2020/formulas/physics/high-school/a4rx7y9xan5ut81we113nicm36as4gqhsx.png)