Question

A tank originally contains 100 gal of fresh water. Then water containing 12 lb of salt per gallon is poured into the tank at a rate of 2 gal/min, and the mixture is allowed to leave at the same rate. After 10 min the process is stopped, and fresh water is poured into the tank at a rate of 4 gal/min, with the mixture again leaving at the same rate. Find the amount of salt in the tank at the end of an additional 10 min. (Round your answer to two decimal places.)

Answer 1

To find the amount of salt in the tank at the end of an additional 10 minutes, calculate the amount of salt added and subtract the amount of salt removed. In this case, 24 lb of salt were added and 0 lb of salt were removed, resulting in 24 lb of salt in the tank.

Step-by-step explanation:

To find the amount of salt in the tank at the end of an additional 10 minutes, we need to calculate the amount of salt added and subtract the amount of salt removed.

In the first 10 minutes, 2 gallons of water containing 12 lb of salt per gallon were poured into the tank at a rate of 2 gal/min, so 2 x 12 = 24 lb of salt were added.

Then, in the next 10 minutes, 4 gallons of fresh water were poured into the tank at a rate of 4 gal/min, so 4 x 0 = 0 lb of salt were added.

Therefore, the amount of salt in the tank at the end of an additional 10 minutes is 24 lb - 0 lb = 24 lb.