Question

A volleyball is spiked so that its incoming velocity of +4 m/s is changed to an outgoing velocity of -22 m/s. The mass of the volleyball is 0.38 kg. What impulse does the player apply to the ball?

Answer 1

`J=-9.88\ kgm/s`

Step-by-step explanation:

It is given that,

Mass of the volleyball, m = 0.38 kg

Incoming velocity of the ball, u = +4 m/s

Outgoing velocity of the ball, v = -22 m/s

The impulse the player apply to the ball is equal to the change in momentum. It can be calculated as :

`J=m(v-u)`

`J=0.38* (-22-4)`

`J=-9.88\ kgm/s`

So, the impulse the player apply to the ball is 9.88 kg-m/s. Hence, this is the required solution.