Question

In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5190 km away, and released. It found its way back to its nest 15.0 days after release. If we place the origin in the nest and extend the +x-axis to the release point, what was the bird's average velocity for the return flight?

Answer 1

The bird's average velocity is 4.00 m/s.

Step-by-step explanation:

Given that,

Distance = 5190 km

Time
`t = 15.0\ days = 1.296*10^(6)\ sec`

We need to calculate the bird's average velocity for the return flight

Using formula of average velocity

`v_(avg)=(d_(i)-d_(f))/(t)`

Where, d = position

t = total time

Put the value into the formula

`v_(avg)=(0-5190*10^(3))/(1.296*10^(6))`

`v_(avg)=-4.00\ m/s`

Negative sign shows the bird is traveling in negative x -axis.

Hence, The bird's average velocity is 4.00 m/s.