Answer:
$ 1813
Explanation:
Given,
Investment of Kevin,
= $ 49000,
Rate of interest = 1.9 % annually,
Thus, his interest,
= 1.9% of 49000
![=(1.9* 49000)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/5tvs49bbyr8hj30m4jgortc7td85mku3zm.png)
![=(93100)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/e199azqb242woshi5aetkjkhofq9flirpg.png)
![=\$ 931](https://img.qammunity.org/2020/formulas/mathematics/high-school/a2v9pxavhb3jq0ukmk7jc66qistqtdth9i.png)
Hence, Kelvin's amount after 1 year,
![A_1=P_1+I_1=49000+931=\$ 49931](https://img.qammunity.org/2020/formulas/mathematics/high-school/mu29ieubxz19flelf343o5prujktvhgfve.png)
Now, Investment of Charles,
= $ 49000,
Rate of interest = 5.6 % annually,
Thus, his interest,
= 5.6% of 49000
![=(5.6* 49000 )/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/6up4vm8k7jfk38o2cq8i3izig3lxudrdef.png)
![=(274400)/(100)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8ial5cajj10j4y90j7cq6zfrmm56um2hfa.png)
![=\$ 2744](https://img.qammunity.org/2020/formulas/mathematics/high-school/ybemizs2eciyifor7j2lg6cmm5wwhqekui.png)
Hence, Kelvin's amount after 1 year,
![A_2=P_2+I_1=49000+2744=\$ 51744](https://img.qammunity.org/2020/formulas/mathematics/high-school/yz35zibk2k0h3a3it0aspehw3t1dftk5s3.png)
![\because A_2-A_1=51744-49931 = \$ 1813](https://img.qammunity.org/2020/formulas/mathematics/high-school/o9p6yubye2f58epv14efyp2hr35td8umfi.png)
Therefore, after 1 year Kevin has $1813 more than Charles.