It depends, but this is how I would do it:
Let's take the square root of -8 -->
![ā(-8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4y4d3qke0e8n6scop2c17kanx96fo14am7.png)
First, I would take out an "i" and put it outside of the square root:
![iā(8)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/yoiuziwks0yr7dl19lw7w1es0educxhxj8.png)
The i represents the negative sign. Then, I would treat the square root of 8 as a normal problem and simplify by factoring it:
Factors of 8: 2,2,2
Because you're looking for a square root and you can "loop" two 2s together, you can take one set out:
would be your final answer.
Hope I helped :)