Question

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)

Answer 1

Option 3: (0,-9)

Explanation:

Description of graphed function:

Minimum value of function = (0,-9)

Maximum values of function = (-2.3,16), (2.3,16)

Crosses the x-axis = (-3, 0), (-1, 0), (1, 0), and (3, 0)

Crosses the y-axis = (0, -9).

We need to find the y-intercept of the graphed function.

y-intercept is the point where the graph of a function intersect the y-axis.

From the given information it is clear that the graph of function intersect the y-axis at point (0,-9). So, the y-intercept of the function is at (0,-9).

Therefore, the correct option is 3.

Answer 2

(0, -9)

Explanation:

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)

The y-intercept is the point where x = 0, and It says there that the graph crosses the y-axis at (0, -9)