Question

A cat is moving at 18 m/s when it accelerates at 4 m/s2 for 2 second. what is his new velocity?

Answer 1

Answer:
`26\ (m)/(s)`

Step-by-step explanation:

His new velocity is the "Final velocity". In order to calculate it, you need to use the following formula:

`V_f=V_0+at`

Where
`V_f` is the Final velocity,
`V_0` is the Initial velocity,
`a` is the acceleration and
`t` is the time.

Based on the information provided in the exercise, you can identify that:

`V_0=18\ (m)/(s)\\\\a=4\ (m)/(s^2)\\\\t=2\ s`

Therefore, you can substitute values into the formula:

`V_f=18\ (m)/(s)+(4\ (m)/(s^2))(2\ s)\\\\V_f=26\ (m)/(s)`

Then, his new velocity is
`26\ (m)/(s)`